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So what
about the derivative of Log8X ?
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Putting
this in an equation, it would be: |
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Y = Log8X
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Now we
already know how to find the derivative of ln X, so we have a
choice. |
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We can
convert the log base on this and use the steps we already know, |
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or try to
figure out a new way to use on these. |
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Here's a
real shock... |
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We're
just going to change the base. |
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The rule
on changing bases is: |
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ln a is a
constant, so when we find a derivative we can basically ignore it. |
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The
derivative of ln X is 1/X, so we can say: |
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So lets
do a problem already!!! |
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Example: |
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Find the
derivative of log8X |
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copyright 2005 Bruce Kirkpatrick |
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