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The
twin of exponential equations are logarithms.
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If we say
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Y = eX
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That also
means ... |
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log eY
= X
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(also
known as ln Y = X)
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Remember
the way you read a log is: |
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Which is
the same thing we said in the beginning ... |
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Y = eX
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(NOTE:
From here on we'll be using ln instead of loge)
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So the
point is: |
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Y
= eX and ln Y = X
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Say the
exact same thing. |
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So let's
talk about the derivatives and integrals of things like |
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ln
X
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When we
went looking for the derivative of eX, we found that it
was eX, |
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give or
take a dX. |
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Wouldn't
it be nice if ln X worked the same way |
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SORRY, No
such luck. |
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But
finding it isn't too bad. |
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Start
with |
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Y
= ln X
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which is
the same thing as saying: |
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X =
eY
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(Don't
worry, we'll be back to ln X before we're done)
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OK, the
derivative of eY (with respect to the variable Y) is eY |
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so we can
say: |
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We can
flip these over and say: |
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Now we do
some substitution. |
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We
started with the equations: |
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Y
= ln X also known as X =
eY
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Now we
substitute both of these into our last equation: |
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In
English, what this says is that the derivative of lnX, |
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is equal to
1/X (also known as X-1) |
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This also
means that the integral of X-1 is lnX, |
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remembering,
of course, to include dX's and + C's where needed. |
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Sometimes
you will see written as  |
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Don't let
that throw you, they both mean the same thing. |
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Examples: |
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Did you
notice the 2X in the numerator of the last one? |
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The
derivative of X2 is 2XdX, so everything we needed
to have, |
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to
"Put Back Into" the 1/X2 was there. |
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So this
all works out great for things like eX and ln X, |
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but what
if you have to deal with 2X or log8X ? |
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Huh??? |
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Well????? |
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copyright 2005 Bruce Kirkpatrick |
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