|
|
|
|
Math is
like a foreign language, the symbols all stand for words and ideas.
|
|
|
The S
symbol, Greek letter capital Sigma, has a fairly involved meaning. |
|
|
It tells
us to sum up a bunch of terms. |
|
|
It is
kind of like a little computer program. |
|
|
|
|
|
How many
terms are we talkin' about? |
|
|
|
|
|
That bit
of info comes from other symbols that are above and below the S. |
|
|
You might
see something like: |
|
|

|
|
|
|
|
|
Maybe
instead of the X you will see a Y or a k or any old letter below the
S. |
|
|
The
important thing is that if you count from the bottom number (here a
1), |
|
|
to the
top number (here a 5) you get the number of terms we add together. |
|
|
|
|
|
1,
2, 3, 4, 5 (5 terms)
|
|
|
|
|
|
If we
had: |
|
|

|
|
|
We would
also have 5 terms. |
|
|
103,
104, 105, 106, 107 (5 terms)
|
|
|
|
|
|
Or: |
|
|

|
|
|
Which
would be: |
|
|
-4,
-3, -2, -1, 0 (5 terms)
|
|
|
|
|
|
WHY THIS
SILLY NOTATION? |
|
|
If you
wanted 5 terms, why not just write "5 terms" under the S
or something? |
|
|
|
|
|
The
reason is that those particular numbers: |
|
|
1, 2, 3, 4, 5 or 103, 104,
105, 106, 107 |
|
|
might be
needed somewhere in the problem. |
|
|
Where we
wrote (stuff), |
|
|
we might
have something like: |
|
|
3X
|
|
|
This
makes the whole expression: |
|
|

|
|
|
Did you
see that the letter under the S
|
|
|
matches the variable in the expression to the right? |
|
|
This
little group of symbols means that we have 5 terms. |
|
|
Each of
the terms is the number 3, raised to a power. |
|
|
The power
is the sequence of numbers. |
|
|
|
|
|
This
particular whole sum is: |
|
|
31 +
32 + 33 + 34 + 35 = 363 |
|
|
|
|
|
Which is
a whole lot different from: |
|
|

|
|
|
Which is: |
|
|
3103
+ 3104 + 3105 + 3106 + 3107
»
1.684 x 1051
|
|
|
|
|
|
Sometimes
there is no variable in the statement. |
|
|
We might
have: |
|
|

|
|
|
Which is
just: |
|
|
4 + 4 + 4 + 4 +
4 + 4 =
24
|
|
|
We have a
total of 6 fours here. |
|
|
That's
the same as 6 x 4. |
|
|
so we can
say that if we're "summing" a term with no variable |
|
|
and the
number under the S
is a 1 |
|
|
the
answer is the number on top times the constant. |
|
|
In math
talk, that is: |
|
|

|
|
|
So: |
|
|

|
|
|
|
|
|
If we
have something like: |
|
|

|
|
|
|
|
|
We get: |
|
|
3(1) + 3(2) +
3(3) + 3(4) + 3(5) =
45
|
|
|
|
|
|
Remember
when we did limits, and derivatives, and integrals? |
|
|
The rules
let us move constants to the left and deal with them later. |
|
|
We can do
that here too. |
|
|
So: |
|
|

|
|
|
|
|
|
Also,
when we worked with limits, and derivatives, and integrals |
|
|
and had a
bunch of terms, like: |
|
|
3X2
+ 4X - 5
|
|
|
|
|
|
We could
work with each term by itself. |
|
|
We can do
that here too. |
|
|
So: |
|
|

|
|
|
|
|
|
Even so,
calculating this out would take a long time. |
|
|
Just the
first part would be: |
|
|
3(12
+ 22 + 32 + 42 + 52)
|
|
|
|
|
|
And these
things can get even more complex. |
|
|
How about
some shortcuts? |
|
|
SURE! |
|
|
|
|
|
If we
have X to the first power: |
|
|

|
|
|
|
|
|
If we
have X to the second power (X 2): |
|
|

|
|
|
|
|
|
If we
have X to the third power (X 3): |
|
|

|
|
|
|
|
|
If we
have some number to the X power (C X): |
|
|

|
|
|
|
|
|
copyright 2005 Bruce Kirkpatrick |
|