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There
is one function where our integral formula does not work.
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If we
have the equation: |
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Then
applying the rule would give us: |
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WOW! Try
to make sense out of that! |
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On second
thought, don't. |
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The real
answer is: |
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OK,
What's an "ln" ??? |
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"ln"
Lower Case "LN" is actually a special type of logarithm, |
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with a base of about 2.71828. |
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The
actual base number is a special irrational number. |
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It is so
special, that it gets it's own letter for a name: "e" |
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This
"e" thing has all kinds of applications, and we'll flog
them to pieces in time. |
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For now,
just remember that: |
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Why do
we need the absolute value sign??? |
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The way logarithms
work, |
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"lnX" means the exponent that 2.71828 needs to be
raised to, to get X. |
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No matter
what power you raise 2.71828 to, you always get a positive number, |
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so we use
the absolute value sign to make sure we know |
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to have a positive
value for X. |
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OK, Fine.
But what if we need the integral of some complex function like: |
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F(x) = (3X
- 5)-1
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What
then??? |
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Well then
we're back to the old outside/inside thing. |
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We need
to have the derivative of the inside part sitting there at the
start. |
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We have |
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| (3X
- 5)-1 which is the same as |
1 |
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| 3X
- 5 |
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And we
need: |
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(3X - 5)-1
3dx which is the same as |
3dx |
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| 3X
- 5 |
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dx is
just 1 so that's no problem, |
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but we need our little change the du
constant trick again... |
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So: |
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The
general form of this "ln" thing is: |
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By the
way, even though we're not really looking for derivatives right now |
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we've
stumbled on the fact that the derivative of lnX is 1/X. |
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Hey, take
what you can get! |
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Another
Example: |
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copyright 2005 Bruce Kirkpatrick |
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