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The
derivatives of trig functions are a bit different. |
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Look at
the sine function, and the slope of the sine function |
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at some
selected points. |
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| F(X)
= sin X |
| X° |
slope |
| 0° |
1 |
| 90° |
0 |
| 180° |
-1 |
| 270° |
0 |
| 360° |
1 |
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Look at
these angles and slope values. |
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At 0°
the value is 1, |
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At 90°
the value is 0, |
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At 180°
the value is -1, |
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At 270°
the value is 0, |
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and at
360°
the value is back to 1. |
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That
looks like the values of the cosine. |
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And it
is: |
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If
F(X) = sinX then
F'(X) = cosX
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That's
like cosmically weird, but that's the way it works. |
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I wonder
if the derivative of the cosine might be the sine? |
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Let's
see... |
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| F(X)
= cos X |
| X° |
slope |
sinX |
| 0° |
0 |
0 |
| 90° |
-1 |
1 |
| 180° |
0 |
0 |
| 270° |
1 |
-1 |
| 360° |
0 |
0 |
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Well it
starts out the same as the sine at zero. |
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But when
the sine goes positive, the slope of the cosine goes negative. |
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And vice
a versa |
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It looks
like the sine but negative ... |
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BINGO! We
have a winner! |
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If
F(X) = cosX then
F'(X) = - sinX
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Not quite
what we were expecting, but close. |
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Sometimes
we don't just have X as the variable. |
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Sometimes
we have something more complicated. |
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Like 2X. |
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OK,
that's not so complicated. |
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But it's
enough. |
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If we
want to find the derivative of F(X) = sin2X, what do we do? |
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It turns
out that this is one of those outside function and inside function
things. |
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The outside part is G(X)
= sin(something)
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And the
inside part is H(X) = 2X (the something!) |
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That
means to find the derivative we use the power chain rule |
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from a
couple of pages ago. |
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So you
don't have to go looking, here it is: |
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If
F(X) = H(G(X))
then F'(X) = H'(G(X))
x G'(X)
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So the
derivative of the sine is the cosine, and the derivative of 2X is 2. |
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Putting
this all together, and remembering |
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that we don't touch the inside
function when we
do the outside derivative, |
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we get: |
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If
F(X) = sin2X then
F'(X) = cos2X ´
2
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which simplifies to
F'(X) = 2cos2X
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OK, 4
more trig functions to go. |
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The deal is,
now we're going to cheat. |
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All of the rest
of the trig functions can be written as functions of sine and
cosine. |
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Then we just use the rules we already have to get the answers. |
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Here's the tangent: |
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So, use the quotient rule: |
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So the derivative of the tangent is the secant squared. |
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Let's see what
we get for the derivative of the cosecant... |
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Now we have a choice here.
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We can do
the derivative as a quotient rule, |
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OR |
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We can
rewrite this as: |
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csc
X = (sin X)-1
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And do a
power chain rule. |
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We did
the quotient rule on the tangent example |
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so lets
do the power chain rule on this one. |
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OK, for
practice you should stop right now |
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and work out the derivatives of
the other 3 trig functions. |
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We'll
wait. |
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Really... |
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Done
already? WOW! |
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There are
three suggestions I have for remembering these 6 derivatives: |
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1) Don't
memorize any of it, but know what the graphs |
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of sine and cosine look
like. |
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Then you
can work it all out when you need it. |
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Yes, this
will take a good bit of time anytime you need one. |
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2) Use a
whole bunch of brute force memorization and memorize all 6. |
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3)
Memorize 3, and use a trick to know the other three with no extra
effort |
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(That one
sounds like a winner, read on to learn the trick) |
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THE TRICK |
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To learn
the derivatives of the 6 trig functions |
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you actually only have to
learn 3 of them. |
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The three
to learn are sine, tangent, and secant. |
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| IF |
THEN |
| F(X)
= sin X |
F'(X)
= cos X |
| F(X)
= tan X |
F'(X)
= sec2 X |
| F(X)
= sec X |
F'(X)
= sec X tan X |
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The other
three functions all start with "co" |
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Cosine,
Cotangent, and Cosecant. |
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Think of
the functions as having partners: |
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| sine |
to |
cosine |
| tangent |
to |
cotangent |
| secant |
to |
cosecant |
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To find
the derivative of the "co" functions, |
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start
with the derivatives of sine, tangent and secant, |
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change
each function in the derivative to it's co-function partner |
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and put a
minus sign in front of the derivative. |
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So
starting with one of the three we need to know: |
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If F(x) =
secant X then F'(x) = secant X tangent X
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So now to
get the derivative of the cosecant: |
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If
F(X) =
cosecant
X then F'(X) =
-
cosecant X cotangent
X
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So all 6
trig function derivatives look like this: |
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| IF: |
THEN: |
| F(X) = sinX |
F'(X) = cosX |
| F(X) = cosX |
F'(X) = - sinX |
| F(X) =
tanX |
F'(X)
= sec2 X |
| F(X) =
cotX |
F'(X)
= - csc2 X |
| F(X) =
secX |
F'(X)
= sec X tan X |
| F(X) =
cscX |
F'(X)
= -csc X cot X |
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copyright 2008 Bruce Kirkpatrick |
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