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So now we
have a step by step process to find X, |
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but wow!
it is really long and involved. |
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It is a
lot to remember! |
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Couldn't
we maybe just have a formula |
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to solve
these things all in one shot? |
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Huh? |
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Please? |
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SURE |
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For the
last two pages, we've been solving stuff like: |
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3X2
+ 5X + 2 = 0
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and |
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X2
- 4X + 3 = 0
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Here's
what we're going to do. |
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We're
going to write one of these equations as ... |
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AX2 +
BX + C = 0 |
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Then
we're going to do our long process from the last page on it. |
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In the
end, we will have ... |
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X = some
junk with A's B's and C's in it
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From then
on, when we have one of these equations |
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all we
have to do is pick out the A, B, and C value |
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and put
it in the formula we are about to build. |
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No more
nasty factoring. |
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Just
remember the formula, and you're set.
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Here we
go: |
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STEP
1: |
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Divide
both sides of the equation by the coefficient on the X2
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Simplify
... |
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STEP
2: |
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Take the
X term and determine the value of B. |
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Use that
to find B2. |
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STEP
3: |
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Put the B
2
value into the equation. |
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STEP
4: |
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Gather up
the terms of the square, |
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and write
them as the square. |
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STEP
5: |
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Put all
of the other baloney that's not part of the square |
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on the
right side of the equation. |
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Simplify
it as much as you can. |
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STEP
6: |
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Solve
this for X. |
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And there
it is! |
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The most
important formula in all of Algebra. |
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It was a
lot of work getting here, |
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but here
is the payoff. |
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Now, if
we have something like ... |
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5X2 -
13X + 6 = 0 |
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We can
say, OK: |
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A =
5 B =
-13 C = 6 |
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and put
these numbers into "THE FORMULA" |
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This is
the same answer as we got before for this one, |
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but this
time it was a whole lot easier. |
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Our new
formula is called ... |
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The Quadratic
Formula |
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When we
use it, sometimes we will get two answers, |
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sometimes
we will get one answer, |
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and
sometimes we will not get any answers. |
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If we
don't get any answers, |
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it
doesn't mean that the formula didn't work. |
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It means
that the problem really doesn't have any answers. |
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There is
a quick way to tell how many answers you will get. |
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Just look
at this part of the formula: |
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If B
2
- 4AC works out to be a positive number, |
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you will
get two answers for X. |
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If B
2
- 4AC works out to be zero, |
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you will
get one answer for X. |
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If B
2
- 4AC works out to be a negative number, |
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you will
not get any answers for X. |
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Because
this piece of the formula can tell you that, |
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it gets
it's own name. |
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It is
called: |
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The Discriminant |
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Let's do
another one ... |
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Example: |
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4X2 -
20X + 25 = 0 |
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So: |
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A =
4 B =
-20 C = 25 |
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The
"discriminant" part of the formula was equal to zero, |
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so we
only get one answer. |
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Example: |
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6X2 =
- 2X + 4 |
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Whoa!
Time out! |
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Before we
do anything, we need to move all of the values |
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over to
the left side of the equation so we have: |
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AX2 +
BX + C = 0 |
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So: |
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A =
6 B =
2 C = -4 |
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copyright 2005 Bruce Kirkpatrick |
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