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Once upon
a time a few pages ago, |
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I
promised you a method to factor some equations directly |
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without
all of the guessing games. |
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Here it
is. |
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Say you
have an equation that looks something like ... |
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6X2
+ 2X - 4 = 0
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We will
be trying to turn this into ... |
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(X ± some
number)2 = some other number |
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So how do
we do it? |
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Well,
when we had (X + 4)2 and multiplied it out, |
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we got
... |
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(X + 4)2
= X2 + 8X + 16 |
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In
general, using the letter "B" to stand for |
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any old
number that we might have |
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we get
... |
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(X + B)2
= X2 + 2BX + B2 |
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This is
what we need to get to. |
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We take
whatever we have at the start |
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and make
it look like X 2
+ 2BX + B 2 |
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So
looking at 6X 2
+ 2X - 4 = 0, |
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the
first thing we need to do is get rid of the 6 part of the 6X
2. |
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To do that,
we divide both sides by 6 ...
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STEP
1: |
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Divide
both sides of the equation by the coefficient on the X
2
... |
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and
simplify ... |
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STEP
2: |
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Take the
X term and determine the value of B. |
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Use that
to find B 2. |
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In this
problem, the X term is 1/3X. |
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Our
formula says this is equal to 2BX. |
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Solve for
B ... |
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So if 1/6
is B then multiply it times itself |
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to get B
2. |
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STEP
3: |
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Put the B
2
value into the equation. |
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We can do
almost anything we want to an equation |
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if we do
the same thing to both sides. |
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STEP
4: |
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Gather up
the terms of the square, |
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and write
them as the square. |
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At this
point, the first three terms on the left side |
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are the
terms of our square. |
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That is,
the (X + B) 2 = X
2 + 2BX + B
2 |
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We can
substitute the square for these three terms ... |
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STEP
5: |
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Put all
of the other baloney that's not part of the square |
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on the
right side of the equation. |
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Simplify
it as much as you can. |
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STEP
6: |
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Solve
this for X. |
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We're
finally at the place where we have ... |
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(X ± some
number)2 = some other number |
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From here
it's easy. |
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We just
peel the onion ... |
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So we
have two answers ... |
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If you
check back a few pages, |
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you'll
see that we got the same answer there too! |
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copyright 2005 Bruce Kirkpatrick |
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